Mathématiques

Question

a=4*(2+x)    b=3*(2y-5)   c=-3*(2x+6)   d=-3a(2a-4)  

a=6*b+6t     b=5x-5y      c=2a+2         d=9x²-6xy

a=3+(x+6)   b=x-(x-9)     c=z+(-3-z²)    d=6-(-a+8)

1 Réponse

  • a = 4*(2+x)    
    a = 4x+8

    b = 3*(2y-5)
    b = 6y-15
      
    c = -3*(2x+6)  
    c = -6x-18

    d = -3a(2a-4)  
    d = -6a²+12a

    (J'imagine qu'ici il faut factoriser)

    a = 6b+6t  
    a = 6(b+t)

    b = 5x-5y
    b = 5(x-y)

    c = 2a+2  
    c = 2(a+1)

    d = 9x²-6xy
    d = 3x(3x-2y)

    a = 3+(x+6)
    a = x+9

    b = x-(x-9)
    b = 9

    c = z+(-3-z²)
    c = -z²+z-3

    d = 6-(-a+8)
    d = a-2

Autres questions