Physique/Chimie

Question

aidez moi svp c très important
aidez moi svp c très important

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1 Réponse

  • 1 - M(C3H6O3) = 3M(C) + 6M(H) + 3M(O) = 3x12 + 6x1 + 3x16 = 90 g/mol
    2 - M(C3H6O3) = V(C3H6O3)x p(C3H6O3) = 30x1.24 = 37.2 g 
    3 - n(C3H6O3) = m(C3H6O3) / M(C3H6O3) = 37.2 / 90 = 0.413 ~ 0.41 mol
    4 - Vm = V(C3H6O3) / n(C3H6O3) = 30 / 0.41 = 73.2 mL

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