Mathématiques

Question

bonjour *
pourriez vous m aider svp ??

on donne les expression suivantes

A(x) = x-2/x-1 B(x) = 1-1/x-1

C(x) = 3-2x/x-1 D(x) = -2+1/x-1

je nes pas vraiment compris les calcul algebrique c est un devoir maison pour demain svp

1 Réponse

  • Bonsoir,

    Quelles sont les expressions qui sont égales :

    A(x) = (x-2) / (x-1)

    B(x) = 1 - 1 / (x-1)
    B(x) = (x - 1)/(x - 1) - 1 / (x - 1)
    B(x) = (x - 1 - 1)/(x - 1)
    B(x) = (x - 2)/(x - 1)
    B(x) = A(x)

    C(x) = 3 - 2x/(x-1)
    C(x) = 3(x - 1)/(x - 1) - (2x) / (x - 1)
    C(x) = (3x - 3)/(x - 1) - (2x) / (x - 1)
    C(x) = (3x - 3 - 2x)/(x - 1)
    C(x) = (x - 3)/(x - 1)

    D(x) = -2 + 1/(x-1)
    D(x) = -2(x - 1)/(x - 1) + 1/(x - 1)
    D(x) = (-2x + 2 + 1)/(x - 1)
    D(x) = (-2x + 3)/(x - 1)

    D(3/2) = (-2 × 3/2 + 3)/(3/2 - 1)
    D(3/2) = (-3 + 3)/(3/2 - 2/2)
    D(3/2) = 0

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