Svp aider moi thksss

b) il y a 16 issues possibles comportant chacune 4 réponses !
     2 puissance 4 = (2²)² = 4² = 16

2°) proba(E) = p(J1;J2;J3;J4) = 1/16 = 0,o625 = 6,25 %
      p(F) = 4 * 1/2 * (1/2)³ = 2 * (1/2)³ = 2 * 1/8 = 1/4 = 0,25 = 25 %
      p(G) = 1 - p(4 fausses) = 1 - 0,o625 = 0,9375 = 93,75 %

      p(2 justes) = 6/16 = 3/8 = 0,375 = 37,5 % --> proportion des Elèves
                                                                                ayant la moyenne ...