Mathématiques

Question

Factoriser ;
A(t) = (2t - 1) (t + 1 ) -2 (t + 1)
B(t) = (5t - 1) (3t + -2) - (5t - 1) au carré

2 Réponse

  • A(t) = (2t -1)(t+1) - 2(t+1)
          = (t +1)(2t -1-2) 
          = (t +1)(2t -3)

    B(t) = (5t-1)(3t-2) - (5t -1)^2
          = (5t -1)(3t -2 - 5t +1)
          = (5t -1)(-2t -1)
  • A(t)=(2t-1)(t+1)-2(t+1)
    A(t)=(t+1)(2t-1-2)
    A(t)=(t+1)(2t-3)

    B(t)=(5t-1)(3t+-2)-(5t-1)^2
    B(t)=(5t-1)(3t-2-5t+1)
    B(t)=(5t-1)(-2t-1)
    B(t)=-(5t-1)(2t+1)

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