Mathématiques

Question

developper, reduire et ordonner les expression
a = (x+3) (x-5)
b = 3(x - 10) - (x+2) (-x + 5)
c = (3x + 5)²

1 Réponse

  • a = ( x + 3 ) ( x - 5 )
    = x * x + x * (-5) + 3 * x + 3 * (-5)
    = x^2 - 5x + 3x - 15
    = x^2 - 2x - 15

    b = 3 ( x - 10 ) - ( x + 2 ) ( -x + 5 )
    = 3 * x + 3 * (-10) - [ x *(-x) + x * 5 + 2 * (-x) + 2 * 5 ]
    = 3x - 30 - [ -x^2 + 5x - 2x + 10 ]
    = 3x - 30 + x^2 + 3x + 10
    = x^2 + 6x - 20

    c = (3x + 5)²
    = (3x)^2 + 2 * 3x * 5 + 5^2
    = 9x^2 + 30x + 25

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